# Line slope calculator 2x+y=19

**Straight line given by points A[7; 5] and B[8; 3]**

## Calculation:

**Slope-intercept form of line:**y = -2x+19

**Canonical form of the line equation:**2x+y-19 = 0

**Parametric form of the line equation:**

x = t+7

y = -2t+5 ; t ∈ R

**Slope:**m = -2

**Slope angle of line: φ =**-63°26'6″ = -1.1071 rad

**X intercept:**x

_{0}= 9.5

**Y intercept:**y

_{0}= q = 19

**Distance line from the origin:**d

_{0}= 8.4971

**The length of the segment AB: |AB| =**2.2361

**Vector: AB =**(1; -2)

**Normal vector: n =**(2; 1)

**Midpoint of the segment AB: M =**[7.5; 4]

**Perpendicular Bisector equation:**x-2y+0.5 = 0

**Vector OA = (7; 5) ; |OA| = 8.6023**

**Vector OB = (8; 3) ; |OB| = 8.544**

**Scalar product OA .OB = 71**

**Angle ∠ AOB = 14°58'54″ = 0.2615 rad**